12c^2-25c+12=

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Solution for 12c^2-25c+12= equation:


Simplifying
12c2 + -25c + 12 = 0

Reorder the terms:
12 + -25c + 12c2 = 0

Solving
12 + -25c + 12c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(3 + -4c)(4 + -3c) = 0

Subproblem 1

Set the factor '(3 + -4c)' equal to zero and attempt to solve: Simplifying 3 + -4c = 0 Solving 3 + -4c = 0 Move all terms containing c to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + -4c = 0 + -3 Combine like terms: 3 + -3 = 0 0 + -4c = 0 + -3 -4c = 0 + -3 Combine like terms: 0 + -3 = -3 -4c = -3 Divide each side by '-4'. c = 0.75 Simplifying c = 0.75

Subproblem 2

Set the factor '(4 + -3c)' equal to zero and attempt to solve: Simplifying 4 + -3c = 0 Solving 4 + -3c = 0 Move all terms containing c to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -3c = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -3c = 0 + -4 -3c = 0 + -4 Combine like terms: 0 + -4 = -4 -3c = -4 Divide each side by '-3'. c = 1.333333333 Simplifying c = 1.333333333

Solution

c = {0.75, 1.333333333}

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